Bulgaria's No.1 male tennis player Grigor Dimitrov won in the second round of the men's singles competition of the Australian Open on Wednesday.

Dimitrov defeated Lukas Lacko from Slovakia with 6:3, 6:7 (10), 6:3, 6:3 in an intense game that lasted almost three hours, electronic daily Dnevnik reports.

The first set started well for the Bulgarian, who made a break and came in the lead with 3:1.

However his opponent recovered quickly, made a break in return and managed to equalise.

Dimitrov achieved a new decisive break and closed the set with 6:3.

The Bulgarian started the second set with an early break, but Lacko returned it immediately.

The set went into a tie-break, in which the Slovak established a 5:3 lead, but Dimitrov won three consecutive points .

Lacko was again in the lead at 11:10, when the Bulgarian made a double fault and conceded the set.

In the third set Dimitrov again made an early break and went in the lead with 3:0.

The Bulgarian continued to play with confidence and won the set with 6:3.

The fourth set followed a similar development – Dimitrov made a break early on and came in the lead with 3:1.

Lacko requested a medical timeout and following his return on the court managed to equalise.

However the Bulgarian achieved two further breaks, closing the set with 6:3 and winning the match.

In the third round the Bulgarian will face Marcos Baghdatis from Cyprus, who defeated the Belgian David Goffin with 6:1, 6:4, 4:6, 6:0.

This will be the seventh match between the two, with Dimitrov having won five times against Baghdatis.

However the Cypriot won their only match at a Grand Slam tournament, when the Bulgarian retired in Wimbledon in 2012.

Their last encounter was a year ago in Acapulco, where Dimitrov won and later claimed the championship title.

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